Question

0.2
A sum of Rs. 2100 when invested in scheme A offering % compound interest (compounded annually) for 2 years amounts to Rs. 2541. Rs P
when invested for 2 years in scheme B offering simple interest at (x+5)% pa, earns an interest of Rs. 1350 What is the value of Pa

Answer 1

Case 1) :- A sum of Rs. 2100 when invested in scheme A offering x% compound interest (compounded annually) for 2 years amounts to Rs. 2541.

Solution :-

→ A = P[1 + (R/100)]^T

→ 2541 = 2100[1 + (x/100)]²

→ 2541/2100 = [1 + (x/100)]²

→ 121/100 = [1 + (x/100)]²

→ (11/10)² = [1 + (x/100)]²

square root both sides,

→ (11/10) = 1 + (x/100)

→ (x/100) = (11/10) - 1

→ (x/100) = (1/10)

→ x = 10% .

Case 2) :- Rs P when invested for 2 years in scheme B offering simple interest at (x+5)% pa, earns an interest of Rs. 1350 What is the value of P ?

Answer :-

→ Rate = (x + 5)% = 10 + 5 = 15% .

so,

→ SI = (P * R * T)/100

→ 1350 = (P * 15 * 2)/100

→ 13500 = 3P

→ P = Rs.4500 (Ans.)

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