Question

0
2) आकृतीमध्ये, 0 हा वर्तुळाचा केंद्रबिंदू आहे.
= 140° असेल, तर mZABC = ?
140°

A
B​

Answer 1

Answer:

Step-by-step explanation:

Answer

Answer 2

Given :- O is the centre of the circle . ∠OAB = 40° .

To Find :-

• ∠ACB = ?

Solution :-

In ∆AOB, we have,

→ OA = OB = radius of the circle .

so,

→ ∠OAB = ∠OBA { Angle opposite to equal sides are equal .}

then,

→ ∠OAB + ∠OBA + ∠AOB = 180° (Angle sum property.)

→ 40° + 40° + ∠AOB = 180°

→ ∠AOB = 180° - 80°

→ ∠AOB = 100° .

therefore,

→ ∠ACB = (1/2) ∠AOB { Angle at the circumference of a circle is half the angle at the centre standing on the same arc .}

hence,

→ ∠ACB = (1/2) * 100°

→ ∠ACB = 50° (Option 2) (Ans.)

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