Chemistry, asked by renukabevara, 11 months ago

0.2 g of sample of H,O, required 10 ml of
1N KMnO, solution in a titration in presence of dil.
H2SO4. The percentage purity of H2O2 is
(1) 25%
(2) 65%
(3) 85%
(4) 95%​

Answers

Answered by Ananya1514
19

Answer:

Explanation:

10 ml of 1N KMnO4 solution is used to titrate 0.2gm of H2O2

Mole of H2O2 = 0.2/34= 0.0588 moles

if this solution is made upto 1 ltr to titrate, we have molarity = 0.0588 M

Since H2O2 release 2 H+ ions, Its normality = 2 x 0.0588 = 0.01174 N

Using equation

N1 V1 = N2 V2

10 * 1 = 0.01174 * V2

V2 = 854ml

Hence effective 854 ml is used in 1000 ml depending on purity

hence Purity of H2O2 is 85.4%

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