Question

0.2 If nC0= 1 then the value of 99C0 is:​

Answer 1

here value of n=1/CO,CO=1/n=CO

99CO=99CO

Answer 2

/* We know that */

$\boxed{ \pink{ ^{n}C_{r} = \frac{n!}{r! \times ( n-r)! } }}$

$Here , given \: ^{n}C_{0} = 1 \: --(1)$

$\red{ Value \: of \: ^{99}C_{0} } \green { = 1}\: \blue { [ From \: (1) ]}$

Explanation:

$\red{ Value \: of \: ^{99}C_{0} } \\= \frac{99!}{ 0! \times ( 99 - 0 )!}$

$= \frac{99!}{1 \times 99 ! }\: \blue{ ( \because 0! = 1 )}$

$= \frac{\cancel {99!}}{ \cancel {99 ! }}$

$= 1$

Therefore.,

$\red{ Value \: of \: ^{99}C_{0} }\green { = 1 }$

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