0.2 kg ball rotates at a constant of 3m/s on the end of 1.2 m long string. The string describes a horizontal circle. What is the centripetal acceleration of the object ?
Answers
Mass of the ball = 0.2 kg
Length of the string = 1.2 cm
Velocity = 3 m/s
The centripetal acceleration of the object.
Here,
➣ a = centripetal acceleration
➣ v = velocity
➣ r = radius
Units :-
➣ a = metres per second (m/s)
➣ v = metres per second (m/s)
➣ r = metre (m)
According to the question :-
➣ a = ?
➣ v = 3 m/s
➣ r = 1.2 m
We should find the centripetal acceleration of the body.
Substituting the values...we get,
_______________________________________
Given info : 0.2 kg ball rotates at a constant of 3m/s on the end of 1.2 m long string. The string describes a horizontal circle.
To find : the centripetal acceleration of the object is ..
solution : length of the string , l = 1.2 m
speed of the ball attached to one of the ends of string, v = 3 m/s
mass of ball , m = 0.2 kg
for a uniform circular motion, the centripetal acceleration of the object is given by, a =
a =
therefore the centripetal acceleration of the object is 7.5 m/s².
[ note : centripetal acceleration is directed radially towards the centre of the circular path. so the centripetal force also acts towards the centre of it and to balance this force, a psuedo force needs to apply just opposite to this force, known as centrifugal force. ]