Question

0.2 kg Bullet is fired from a 5 kg gun with a velocity 200 per second the recoil of the gun is​

Answer 1

Answer:

Let mass and velocity of ball be m1=0.05kg and velocity v1=200m/s.

Let mass of gun be m2=5kg and recoil velocity be v2

Use conservation of momentum.

m1v1=m2v2

(0.05)×(200)=(5)v2

V2=2m/s.

Explanation:

hope this will help u

plz follow me