Question

0.2 m solution of formic acid is ionized 3.2% its ionization constant is

Answer 1

K = Ca²

C = 0.2

a = 0.032

So, k = (0.2)(0.032)²

= 2×10-¹×1024×10-6

= 2048×10 raise to -7

= 2.048×10-⁴.