Question

0.2 mol of HCl and 0.1 mol of barium chloride dissolved in water to produce a 500 mL solution.The molarity of Cl- is ?

Answer 1

Answer:

=> Molarity: molarity M = Total moles of solute/ Volume of solution in liter. Therefore, the molarity of CL- in solution is 0.8 M.

Answer 2

Explanation:

First calculate total number of cl- ions.

One mole Nacl will dissociate to give one mole Na+ and one mole cl-. So .2 mole will give .2 mole cl-

One mole bacl2 will dissociate to give one mole ba2+ and 2 mole cl-. So .2 mole will give .4 mole cl-

So the total moles of cl- are .4+.2=.6

Molarity is total moles of solute divided by volume of solution in L. So the molarity is .6/.5= 1.2M