Question

0.2 mol of HCl and 0.1 mol of barium chloride were dissolved in water to produce a 500 mL solution. The molarity of the Cl– ions is

Answer 1

Answer:

0.8 M

Explanation:

Number of moles of HCl is 0.2 mole.

HCl→H  +  +Cl-

Thus, 0.2 mole of HCl gives 0.2 moles of chloride ions.

Number of moles of CaCl 2   is 0.1 mole.

CaCl2  →Ca2+ +2Cl  −

 

Thus, 0.1 mole of CaCl  2  gives (0.1×2) mole of chloride ions.

0.1 mole of CaCl  2  gives 0.2 mole of chloride ions.

Therefore, total number of moles for Cl  −  ions is (0.2+0.2) mole that is 0.4 mole

Now, molarity =  Volume (L)  / Number of moles

​  

 

Volume gives is 500 mL (0.5L)

Molality =   0.5 /0.4

​  

 

Molality=0.8M

​