0.2 moles of glucose is dissolved in 64g of water. Find % w/w, % w/v and molarity. Please answer this properly, don't soam, unless I will report them who will give irrelevant answers.
Answers
Answer: please follow me
Explanation:
The problem gives you all the information you need in order to solve for the molality and mole fraction of the solution. In order to determine its molarity, you're going to need the solution's volume.
To get the volume, you have to know what the density of the solution is. Determine the percent concentration by mass of the solution first
%w/w
=
m
solute
m
solution
⋅
100
In your case, the mass of the solution will be
m
solution
=
m
glucose
+
m
water
m
solution
=
20
+
150
=
170 g
This means that you get
%w/w
=
20
g
170
g
⋅
100
=
11.8%Use glucose's molar mass to determine how many moles you have
20
g
⋅
1 mole glucose
180.16
g
=
0.111 moles glucose
The solution's volume will be
170
g
⋅
1 mL
1.045
g
=
162.7 mL
This means that its molarity is - do not forget to convert the volume to liters!
C
=
n
V
=
0.111 moles
162.7
⋅
10
−
3
L
=
0.68 M
A solution's molality is defined as the number of moles of solute divided by the mass of the solvent - in kilograms! This means that you haveA solution's molality is defined as the number of moles of solute divided by the mass of the solvent - in kilograms! This means that you have
b
=
n
m
water
=
0.111 moles
150
⋅
10
−
3
kg
=
0.74 molal
To get the mole fraction of sucrose, you need to know how many moles of water you have present. Once again, use water's molar mass
150
g
⋅
1 mole water
18.02
g
=
8.24 moles water
The total number of moles the solution contains is
n
total
=
n
glucose
+
n
water
n
total
=
0.111
+
8.24
=
8.351 moles
This means that the mole fraction of sucrose, which is defined as the number of moles of sucrose divided by the total number of moles in the solution, will be
χ
sucrose
=
n
sucrose
n
total
=
0.111
moles
8.351
moles
=
0.013
Explanation:
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