0.2 moles of HCL and 0.2 mole of bacl2 were dissolved in water to produce 500 ml solution the molarity of CL minus ion is
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One mol of HCl will give one mol of H+ and one mol of Cl− when dissociates.
Thus, 0.2 mol gives 0.2 mol Cl−
One mol of BaCl2 will give one mole of Ba2+ and
2 mol of Cl− when dissociates.
Hence, 0.1 mol will give 2 mole Cl−
So the total moles of Cl− are 0.2+0.2 = 0.4
Molarity M = Total moles of solute/ Volume of solution in liter.
M = 0.40.5=0.8M
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