Question

(0.2) n =0.00032 find n

Answer 1

0.2n = 0.00032
n = 0.00032/0.2
n = 0.0032/2
n = 0.0016

Answer 2

The value of n = 5

Given :

$\displaystyle \sf{ {(0.2)}^{n} = 0.00032 }$

To find :

The value of n

Solution :

Step 1 of 2 :

Write down the given equation

Here the given equation is

$\displaystyle \sf{ {(0.2)}^{n} = 0.00032 }$

Step 2 of 2 :

Find the value of n

$\displaystyle \sf{ {(0.2)}^{n} = 0.00032 }$

$\displaystyle \sf{ \implies {(0.2)}^{n} = 0.2 \times 0.2 \times 0.2 \times 0.2 \times 0.2 }$

$\displaystyle \sf{ \implies {(0.2)}^{n} = {(0.2)}^{5} }$

$\displaystyle \sf{ \implies n = 5 }$

Hence the required value of n = 5

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