Question

0.2
Shivank thought of the least number x which when divided by 12, 15 20 & 21 gave a remainder 10 in each case and x is a multiple of 11. Shivank added a least
number y to make x a perfect square. Find y?​

Answer 1

Answer:

11

Step-by-step explanation:

LCM of numbers= 420

x leaves 10 as remainder in each case

then value of x=420+10=430

y was added to make it a perfect square

nearby square=441

441-430=11

y= 11

Answer 2

Answer:

71

Step-by-step explanation:

lcm=420

to get rem 10. add 420+10

it must be multiple of 11

so, 420k+10

= 418k+(2k+10)

now to make multiple of 11 since 418k is multiple of 11 check for (2k+10) must be multiple of 11 put k=1,2,3,4...etc

we find for k=6 (22) is multiple is 11 so X = 420*6+10

thus , X = 2530

nearest perfect square is 51*51=2601

so Y = 2601 - 2530

= 71