Question

0.2 X + 0.3 Y = 1.3 0.4X + 0.5Y = 2.3 by substitute method

Answer 1

0.2x+0.3y=1.3

(0.2x+0.3y)×10=1.3×10

2x+3y=13 ---[1]

0.4x+0.5y=2.3

(0.4x+0.5y)5=2.3×5

2x+2.5y=11.5 ---[2]

Eq. [1]-[2]

2x+3y-2x-2.5y=13-11.5

0.5y=1.5

5y=15

y=3

x=(13-3y)/2=(13-3×3)/2=2

Answer 2

Hey!!
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0.2x + 0.3y = 1.3---------(1)

0.4x + 0.5y = 2.3--------(2)

From eq'n (1)

0.2x + 0.3y = 1.3

=> 0.2x = 1.3 - 0.3y

=> x = 1.3 - 0.3y / 0.2---------(3)

Substitute eq'n (3) in eq'n (2) we get

0.4x + 0.5y = 2.3

=> 0.4 ( 1.3 - 0.3y / 0.2 ) + 0.5y = 2.3

=> 0.52 - 0.12y + 0.1y = 0.46

=> - 0.02y + 0.52 = 0.46

=> - 0.02y = 0.46 - 0.52

=> - 0.02y = - 0.06

=> y = 0.06 / 0.02× 100 / 100 ( remove decimal )

=> y = 3



From eq'n (1)

0.2x + 0.3y = 1.3

=> 0.2x + 0.3 ( 3 ) = 1.3

=> 0.2x + 0.9 = 1.3

=> 0.2x = 1.3 - 0.9

=> 0.2x = 0.4

=> x = 0.4 / 0.2 × 10/ 10 ( remove decimal )

=> x = 2

Therefore the value of x = 2 and y = 3


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Hope it will helps you☺☺