Question

0.20 g of organic compound gave 0.5544 g of BaSO4. The
percentage of S is
A 38%
B 19%
C 18%
D 83%​

Answer 1

Here's your answer!

• Molar mass of BaSO4 = 233.38 g

• Mass of the compound = (x) g

• Mass of BaSO4 formed = 0.5544 g

We know that 32 grams of sulphur are present in 1 mol of BaSO4

Therefore, 233.38 g BaSO4 contains 32 g sulphur

• 0.5544 of BaSO4 contains 32 × 0.544 × 233.38 grams of sulphur.

• Percentage of sulphur = 32 × 0.5544 × 100 / 233.38 × 0.20

• 1774.08 / 46.676 = 38%

OPTION (A) IS THE ANSWER.

Hope it helps!