0.20 mol sample of MgCl2(s) and a 0.10 mol sample of KCl(s) are dissolved in water and diluted to 500 mL. What is the concentration of CI in the solution?
0.15 M
0.30 M
0.50 M
0.60 M
1.0 M
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Answer:
Moles of chloride ions by potassium chloride = 0.10 moles
Total moles = 0.40 + 0.10 moles = 0.50 moles
Given, Volume = 500 mL = 0.5 L (1 mL = 10⁻³ L)
Concentration of chloride ions is:
Molarity=Moles of solute/Volume of the solution
=0.50/0.5=1M
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