Question

0.200 mol of calcium fluoride, CaF2, is added to 50.0 cm3 of distilled water which is then made up to a total volume of 250 cm3. Determine the concentration of the solution, in mol dm–3.

Answer 1

Answer:

$0.8 moldm^{-3}$

Explanation:

We are given that

Number of moles of solute (calcium flouride)=0.2 mole

Volume of solvent=$50.0 cm^3$

We know that 1 cm=$\frac{1}{10}$ dm

Volume of solution=$250 cm^3=250\times 10^{-3}$

We have to determine the concentration of solution in $moldm^{-3}$

We know that concentration of solution=Molarity of solution

Molarity of solution=$\frac{no.\;of\;moles\;of\;solute}{volume\;of\;solution}$

Substitute the values in the given formula

Then, we get

Concentration of solution=$\frac{0.20}{250\times 10^{-3}}=0.8 moldm^{-3}$

Hence, the concentration of solution=$0.8 moldm^{-3}$