Question

0.21 Which of the following
trains in non - uniform
motion?
Distance coverd (km)
Time Train x & Train y
6:00 AM
5
5
6:30AM
10
15
7:00 AM
15
22​

Answer 1

Answer:

let me explain with example

Key Concepts

Distance, Rate, and Time

D = rt where D = distance, r = rate, t = time

Problem-Solving Strategy—Distance, Rate, and Time Applications

Read the problem. Make sure all the words and ideas are understood.

Draw a diagram to illustrate what it happening.

Create a table to organize the information: Label the columns rate, time, distance. List the two scenarios. Write in the information you know.

Identify what we are looking for.

Name what we are looking for. Choose a variable to represent that quantity.

Complete the chart.

Use variable expressions to represent that quantity in each row.

Multiply the rate times the time to get the distance.

Translate into an equation.

Restate the problem in one sentence with all the important information.

Then, translate the sentence into an equation.

Solve the equation using good algebra techniques.

Check the answer in the problem and make sure it makes sense.

Answer the question with a complete sentence.

Practice Makes Perfect

EXAMPLE:-A train leaves new delhi railway station at 9:00 A.M. and reaches jaipur , which is at a distance of 260 km at 12:45 PM . The train reaches alwar ( at distance 150 km from new delhi ) at 11:30AM and stops there for 15 minutes .

1) what is the reference point for the motion of the train ?

2) What is the average speed of the train between altar and Jaipur ?

SOLUTION:-

I) The reference point should be at Delhi because all distances and time are measured from there only.

II) Distance betweeen alwar and jaipur = 260-150 = 110km

train starts from alwar at 11:45 as it stops for 15 minutes after reaching alwar at 11:30

Therefore, time taken by the train to reach jaipur from alwar = 12:45 - 11:45 = 1 hour

Average speed of the train = Total DistanceTotal Time = 110×1 = 110 Km/Hr