Question

0.210. Find the value of 'x'.
(1) tan 3x = sin 45ºcos 45° + sin 30°
(2) sin 2x = sin 60° cos 30° - cos 60° sin 30°​

Answer 1

Answer:

• tan 3x = 1/√2×1/√2+1/2

tan 3x = 1/2+12

tan 3x =(1+1)/2√3/2×

tan 3x = 2/2

tan 3x =1

3x =tan inverse 1

3x =45°

x = 15°

• sin 2x =√3/2×√3/2-1/2×1/2

sin 2x = 3/4-1/4

sin 2x = (3-1)/4

sin 2x =2/4

sin 2x =1/2

2x = sin inverse 1/2

2x = 30°

x = 15°

x = 15°,15°

Step-by-step explanation:

hope it helps you✌️✌️

Answer 2

Answer:

1) sin45°=1/√2

cos45°=1/√2

sin30°=1/2

tan3x=(1/√2)x(1/√2)+1/2

tan3x=1/2+1/2

tan3x=1

3x=tan^-1(1)

tan45°=1

3x=45°

x=15°

2)sin60°=√3/2

cos30°=√3/2

Cos60°=1/2

sin30° =1/2

sin2x=(√3/2)*(√3/2)-(1/2)(1/2)

sin2x=3/4-1/4

sin2x=1/2

2x=SIN^-1(1/2)

2X=30°

x=15°