0.220 gm of gas occupies a volume of 112 ml at a pressure of 1bar and temperature of 273 K. The gas can be
A) NO2
B) N2O
C) CO2
D) C3H8
Answers
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0.22gm = 112 ml
X GM. = 22400 ml
22400x0.22/112 =44gm
molecular mass of CO2 =44gm
Ans C. OPTION
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