Question

0.23 In figure, lines AB and CD intersect at 0. If ZAOC + BOE = 70° and BOD = 40", find BOE and reflex
LCOE
с
B В​

Answer 1

Given

$\blue\star$AOC + BOE = 70°

$\blue\star$BOD =40°

FIND

$\blue\star$BOE AND REFLEX COE

Solution

$\blue\star$AOC + BOE = 70°

$\blue\star$40° + BOE = 70° (BOD =AOC = 40° VOA)

$\blue\star$BOE = 70 - 40

$\blue\star$BOE =30

$\blue\star$AOC + COE + BOE = 180° (LP)

$\blue\star$70 + COE = 180°

$\blue\star$COE = 110

$\blue\star$Reflex angle COE = 360 - 110 = 250°

Hope it helps.

Answer 2

Question :-

In figure, lines AB and CD intersect at 0. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE.

Answer :-

Since AB is a straight line,

∴ ∠AOC + ∠COE + ∠EOB = 180°

or (∠AOC + ∠BOE) + ∠COE = 180° or 70° + ∠COE = 180° [ ∵∠AOC + ∠BOE = 70° (Given)]

or ∠COE = 180° – 70° = 110°

∴ Reflex ∠COE = 360° – 110° = 250°

Also, AB and CD intersect at O.

∴∠COA = ∠BOD [Vertically opposite angles]

But ∠BOD = 40° [Given]

∴ ∠COA = 40°

Also, ∠AOC + ∠BOE = 70°

∴ 40° + ∠BOE = 70° or ∠BOE = 70° -40° = 30°

Thus, ∠BOE = 30° and reflex ∠COE = 250°.

Plz mrk as brainliest ❤