Question

0.24 gram of gas dissolved in one litre of water at 1.5 ATM pressure calculate the amount of dissolved gas when the pressure is rise to to 6.0 ATM at constant temperature​

Answer 1

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Answer 2

Answer:

0.96 g/L

Explanation:

Psulute = KH xsolute in equation  

At pressure 1.5 atm, p1 = KH x1 …(1)

At pressure 6.0 atm, p = KH x2 ……(2)  

Dividing equation (1) by (2)

We get,

P1/P2 = X1/X2

1.5/6.0 = 0.24/X2

∴ X2 = 0.24×6.0/1.5          

        =0.96 g/L