0.24 gram sample of compound of Oxygen and Boron was found by analysis to contain 0.096 of Boron and 0.144 gram of oxygen calculate the percentage composition of the compound by mass
Answers
Answered by
19
➽━━━━━━━━━━━━━──➸
☺ Hello mate__ ❤
◾◾here is your answer.
Mass of boron = 0.096g
Mass of oxygen = 0.144g
Mass of sample = 0.24g
Thus, percentage of boron by weight in the compound =( 0.0960 × 100)/0.24 = 40%
Thus, percentage of oxygen by weight in the compound = (0.144× 100)/ 0.24 = 60 %
➽━━━━━━━━━━━━━──➸
I hope, this will help you.☺
Thank you______❤
✿┅═══❁✿ Be Brainly✿❁═══┅✿
Similar questions