0.2422g of organic compound gives 0.3269g of barium sulphate. Find percentage of sulphur in the compound.
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Atomic mass of BaSO4=137+32+4×16=233g
233gBaSo4gives32g of sulphur
1gBaSO4 gives 32/233g sulphur
.°.0.3269BaSO4 gives 32/233×0.3269g of sulphur
That comes out 0.045 (apx)
Now %of sulphur=0.045/0.2422×100g
=18.53%
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