Question

0.24g of sample of compound of oxygen and boron was found by analysis to contains 0.96g of boron and 0.144g of oxygen. calculate the percentage composition of the compound by mass​

Answer 1

Answer:

Mass of compound = 0.24 g and, mass of boron = 0.096 g percentage of boron in the compound = mass of boron / mass of compound * 100 = 0.096/0.24 * 100 = 40% mass of oxygen = 0.144 g again, mass of compound = 0.24 g percentage of oxygen in compound = mass of oxygen/mass of of compound * 100 = 0.144/0.24 * 100 = 60% thus ...

Explanation:

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