Question

0.24g of volatile substance displaced 53.78ml of air at STP. The molecule weight of substance is​

Answer 1

Answer:

0.24 g of a volatile substance gives 45 ml at STP.

22400 ml (or 1 mole) at STP will give

45

0.24

×22400=119.47 g.

The vapour density is one half the molecular weight.

Vapour density = mol.wt/2 = 119.47/2

=59.73.