Question

0.25 (4f – 3) = 0.05 (10f – 9)

Answer 1

Answer:

Given,0.25(4f−3)=0.05(10f−9)

⟹

100

25

(4f−3)=

100

5

(10f−9)

⟹25(4f−3)=5(10f−9)[Onmultiplyingbothsidesby100]

⟹5(4f−3)=10f−9[]Ondividingbothsidesby5]

⟹20f−15=10f−9

⟹20f−10f=−9+15[Transposing10ftoLHSand−15toRHS]

⟹10f=6

⟹f=

10

6

or

5

3

Step-by-step explanation:

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Answer 2

Solution :-

0.25 (4f – 3) 0.05 (10f – 9)

f – 0.75 = 0.5f – 0.45

f – 0.5f = – 0.45 + 0.75

0.5f = 0.30

f = 0.30/0.5 = 0.6

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