Question

0.25(4y-3) =0.5y-9solve L.H.S =R.H.S

Answer 1

Answer:

0.25(4y-3)=0.5y-9 (L.H.S=R.H.S)

1y-0.75=0.5y-9

1y-0.5y = -9+0.75

0.5y = -8.25

y = -8.25/0.5

y = -82.5×10/0.5×10

y = -82.5/5

y = -16.5

(L.H.S=R H.S)

Putting y = -16.5

0.25(4×(-16.5)-3) = 0.5×(-16.5)-9

1×(-16.5)-3 = -8.25-9

-16.5-3 = -8.25-9

-19.5 = -19.25

(L.H.S = R.H.S)

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