Question

0.25 gm of a sample of common salt contain 0.1518 gm of chlorine while 0.24 gm of another sample contain 0.1458 gm of chlorine .show that these result are in agreement of law of constant proportion.​

Answer 1

Explanation:

(given)

• 0.25 gm of a sample of common salt contain 0.1518 gm of chlorine
• 0.24 gm of another sample contain 0.1458 gm of chlorine

ratios are

0.25 / 0.1518 = 0.24 / 0.1458

1.6460 = 1.6460

hence proved..

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Answer 2

Law of constant proportion

Explanation:

The Law of constant proportion states that chemical compounds are made up of elements that are present in a fixed ratio by mass.

The Law of constant proportion is known as Proust law or Law of Definite Proportions.

For example, NaCl has a 1:1 mass ratio and it will remain the same.

in 1 sample NaCl mass is 0.25 gm and the mass of Cl is 0.1518 gm, so the mass of Na is 0.0982 gm.

the ratio of 1st sample is= $\frac{0.1518}{0.0982}$

                                        = 1.54

in the 2nd sample,  NaCl mass is 0.24 gm, and the mass of Cl is 0.1458 gm, so the mass of Na is 0.0942 gm

the ratio of 2nd sample is =$\frac{0.1458}{0.0942}$

                                         =1.54

hence, this question obeys the law of constant proportion