Question

0.25 mol of an ideal monoatomic gas undergoes isothermal expansion from a volume of 2.0 dm3 to 10 dm3 at 27°c. Calculate the maximum work that can be obtained from this process.

Answer 1

Answer:

Maximum work is done in isothermal process and is -1.002kJ

Explanation:

Work= 2.303nRTlog($\frac{V1}{V2}$) where V1 and V2 are initial and final volume respectively

∴ W=2.303(0.25)(8.31)(300)log(2/10)

      =-(1436)log(5)

      =-1002.35J = -1.002kJ

Here negative sign indicates that work is done by the gas, i.e the gas expands isothermally.

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