0.25 mol of NH³ is formed when 0.5 mol of N² is reacted with 0.5 mol of H² . What is the percent yeild ?
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h2 is limiting reagent
3mole h2 make 2 mole of NH3.
So 0.5 mole h2 make 0.33 mole NH3
Hence %yield 》0.25÷0.33×100 =76%(approx)
3mole h2 make 2 mole of NH3.
So 0.5 mole h2 make 0.33 mole NH3
Hence %yield 》0.25÷0.33×100 =76%(approx)
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