Question

0.25 mol of NH3 is formed when 0.5 mol of N2 is reacted with 0.5 mol of H2. What is the percent yeild ?

Answer 1

3 mole of h2 make 2 mole of NH3(h2 is limiting reagent).Hence 0.5 mole h2 make .33mole NH3.
SO PERCENTAGE YIELD=
0.25÷0.33×100=76%(approx)