Question

0.250 g of an element M react with excess flourine to produce .547 g of hexaflouride MF6. What is the element?

Answer 1

Go through the following attatchment:

Answer 2

Answer:

The element is molybdenum .

Explanation:

$M+6F\rightarrow MF_6$

Moles of  M = $\frac{0.250 g}{M.M}$

Moles of hexafluoride=$\frac{0.547 g}{(M.M+6\times 19 )g/mol}$

M.M =molar mass of element M.

1 mole of element M gives 1 mole hexafluoride.

Mole of M = mole of hexafluoride

$\frac{0.250 g}{M.M}=\frac{0.547 g}{(M.M+6\times 19 )g/mol}$

M.M = 95.95 g/mol

The element is molybdenum.