Question

0.250 L of a gas is at 0.99 atm and 20 °C. What volume does this air occupy at 37 °C and 0.98 atm? (answer in liters)

Answer 1

Answer:

Explanation:

P1 = 0.99

V1= 0.25L

T1= 273+20 = 293K

P2= 0.98

T2= 273+ 37= 310K

Answer 2

Here we have to use the combined gas law :

$\frac{P1V1}{T1} =\frac{P2V2}{T2}$

where P = pressure(atm/Pa) , V = volume($cm^{3}$)  , T = temperature(°C)

First let's convert litres to cm^{3} = 0.25 × 1000 = 250 cm^{3}

So the volume is :

( 0.99 × 250) ÷ 20 = ( 0.98 × V2) ÷ 37

12.375 = (0.98V) ÷ 37

0.98V = 457.875

V = 467 cm^{3} (3 s.f.)

So to convert cm^{3} to litre :

467 ÷ 1000 = 0.476 Litres

Therefore the Volume is 0.467 Litres