Question

0.255gm of an organic compound is analysied by Kjeldahl's method .the evolved ammonia was completely neutralised by 30ml N/10 shulfuric acid .the percent of nytrogen is​

Answer 1

Answer:

11th

Chemistry

Organic Chemistry - Some Basic Principles and Techniques

Quantitative Analysis

A sample of 0.50 g of an or...

CHEMISTRY

Asked on November 22, 2019 byCharlotte Ramekar

A sample of 0.50 g of an organic compound was treated according to Kjeldahl's method. The ammonia evolved was absorbed in 50 mL of 0.5 M H2SO4.The residue acid required 60 mL of 0.5 M solution of NaOH for neutralisation. What would be the percentage composition of nitrogen in the compound?

A

50

B

60

C

56

D

44

HARD

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ANSWER

Mass of organic compound = 0.50 g

60 mL of 0.5 M solution of NaOH is required by residual acid for neutralisation 

⇒ 60 mL of 0.5 M solution of NaOH = 260 mL of 0.5M H2SO4 = 30mL of 0.5M H2SO4

∴ Acid consumed in absorption of evolved ammonia is (50-30)mL = 20mL

Again, 20mL of 0.5M H2SO4 = 40mL of 0.5M NH3

Since 1000mL of 1M NH3 contains 14g of nitrogen,

∴ 40mL of 0.5M NH3 will contain = 100014×40×0.5 = 0.28g of N

Therefore, percentage of N in 0.50g of organic compound = 0.500.28×100=56%

Hence, the correct answer is 56%

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Answer 2

Answer:

11 is your answer......