Question

0•278 g of magnesium when dissolved in dilute HCI evolved 218•2 mL
of hydrogen at 17°C and 754.5 mm collected over water Find the equivalent weight of the metal
ve (Vapour pressure of water at 17°C = 14.4 mm).
​

Answer 1

Answer:

Mole of H

2(n)

=

RT

PV

=

760×1000×0.0821×293

(780.4−17.4)×119.7

=5×10

−3

Let eq. wt. of metal be E.

Eq. of metal = Eq. of H

2

E

0.275

= mole of H

2

×2=2×5×10

−3

E=27.52