0.28. Find the roots of the following quadratic equation:
√3x² – 2√2x- 2√3=0 please give accurate and full explained solution
Answers
Answered by
31
EXPLANATION.
Quadratic equation.
⇒ √3x² - 2√2x - 2√3 = 0.
As we know that,
⇒ D = Discriminant Or b² - 4ac.
⇒ D = (-2√2)² - 4(√3)(-2√3).
⇒ D = 4 x 2 + 4(√3)(2√3).
⇒ D = 8 + 4(6).
⇒ D = 8 + 24.
⇒ D = 32.
⇒ x = - b + √D/2a.
⇒ x = -(-2√2) + √32/(2√3).
⇒ x = 2√2 + 4√2/(2√3).
⇒ x = 6√2/(2√3).
⇒ x = 3√2/(√3). = √6.
⇒ x = - b - √D/2a.
⇒ x = -(-2√2) - √32/(2√3).
⇒ x = 2√2 - 4√2/(2√3).
⇒ x = - 2√2/(2√3).
⇒ x = -√2/√3.
MORE INFORMATION.
Nature of the roots of the quadratic expression.
(1) = Real and unequal, if b² - 4ac > 0.
(2) = Rational and different, if b² - 4ac is a perfect square.
(3) = Real and equal, if b² - 4ac = 0.
(4) = If D < 0 Roots are imaginary and unequal Or complex conjugate.
Similar questions