0.28 g of ammonia on decomposition gave 0.25 g of nitrogen and rest
hydrogen. What will be the volume of hydrogen evolved at NTP.
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Given info : 0.28 g of ammonia on decomposition gave 0.25 g of nitrogen and rest hydrogen.
To find : What will be the volume of hydrogen evolved at NTP ?
solution : decomposition of ammonia,
2NH₃ (g) ⇒ N₂ (g) + 3H₂ (g)
mass of Ammonia = 0.28 g
molecular weight of ammonia = 17 g/mol
so, no of moles of ammonia = 0.28/17 = 0.0165 mol
but we see,
2 moles of ammonia decomposes into one mole of nitrogen and three moles of hydrogen.
so, no of moles of hydrogen = 3/2 × 0.0165 mol
= 0.02475 mol
now volume of hydrogen gas = 22.4 × no of moles of hydrogen gas
= 22.4 × 0.02475
= 0.5544 Litre
= 554.4 ml
Therefore the volume of evolved hydrogen gas is 554.4 ml
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