Question

0.28 In a given figure, AB= AC and D is the midpoint of BC
i) State 3 pairs of equal parts in ∆ ADB and
∆ ADC.
ii)Is A ADB: AADC? Give reason.
iii) Is <B=<C? Why?​

Answer 1

Here in \Delta ADB and \Delta ADC.

i) Three pair of equal parts are:

AD = AD ( common side )

BD = CD ( as d is the mid point of BC)

AB = AC (given in the question)

ii) Now,

by SSS Congruency rule,

\Delta ADB\cong \Delta ADC

iii) As both triangles are congruent to each other we can compare them and say

\angle B = \angle C.

Answer 2

Answer:

Here in  and

i) Three pair of equal parts are:

AD = AD ( common side ) 

BD = CD ( as d is the mid point of BC)

AB = AC (given in the question)

ii) Now, 

 by SSS Congruency rule,

iii) As both triangles are congruent to each other we can compare them and say

.