Question

0-29 in the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC is
diameter. Find the area of the shaded region.​

Answer 1

Answer:

Area of quadrant - Area of triangle

πr2 × 1/4 - 1/2 × b× h

22/7 × 14× 14 × 1/4 - 1/2 × 14×1

11 × 14 - 7×14

154 - 98

= 56

by Pythagoras formula

H² = P² + B²

H² = 14² + 14²

H. = √14² + 14²

Step-by-step explanation:

H = 14√2

D= 14√2

D= r÷2

D = 14√2 ÷ 2

D = 7√2

semicircle area = πr² × 1/2

22/7 × 7√2 × 7√2 × 1/2

11 × 2 × 7 = 154

154 - 56 = 98

hence answer