0.290 g of an organic compound containing C, H and O on complete [05] \ combustion yielded 0.66g of CO2 and 0.27 g of water. The vapor density of a compound is 29. Determine M.F. of a compound.
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Answer:
O2 make me brainlest Answer
Explanation:
Correct option is
D
C
2
H
4
O
2
Moles of C= moles of CO
2
=
44
0.44
=0.01 moles
Moles of H=2×moles of H
2
O=2×
18
0.18
=0.02 moles
Weight of oxygen = ( 0.30 - weight of carbon and hydrogen ) = (0.3−0.01×12−0.02×1)=0.16 gm
Moles of O=
16
0.16
=0.01 moles
Empirical formula =CH
2
O
Empirical formula mass =30 gm
n=
30
60
=2
Formula=(CH
2
O)
n
=C
2
H
4
O
2
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