Question

0.2964 g of a divalent metal 'M' was deposited at cathode
on a passage of a current of 0.5 ampere for 30 minutes
through a solution of metallic salt. Calculate atomic weight
of the metal.​

Answer 1

Answer:

The solution of a salt of a metal of atomic mass 112 was electrolysed for 15 minutes with a current of 1.5 ampere. The mass of the metal deposited was 0.788 g.

Explanation:

Answer 2

Answer:

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Given that,

Weight of copper =0.2864 g  

Current =0.5 ampere

Time =30 mint

Now we get

Quantity of charge passed

⇒0.5×30×60=900 coulomb

So, 900 coulomb Deposit copper =0.2864g

We know that

1 faraday=96500 coulomb

Thus,

96500 coulomb deposit copper=  

900

0.2864

​  

×96500=30.78 g

Hence, Equivalent mass of copper =30.78g