Math, asked by amrudhashree067, 1 month ago

0(2a−3b)(2a+3b)+(2b+5a)+6a+8(a+2)(−2)(x+2)=0 ​

Answers

Answered by superdupershenron123
0

Answer:

0(2a−3b)(2a+3b)+(2b+5a)+6a+8(a+2)(−2)(x+2)=0 ​

2b+5a+6a+8a+16×-2(x+2)=0

10a+19b+16×(-2x-4)=0

10a+19b-32x-63=-16

10a+19b-32x=47

a+b-x=47/10+19-32

a+b-x=47/-3

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