Question

0.2g of a sample of H2O2. Reduced 20 ml of 1M kMnO4 a solution in aci
dic medium what is percentage purity of h2 O2

Answer 1

Heya,

Here's your answer....

In 0.2 g of a sample of H2O2,

Let ''x'' gm of pure H2O2 is present, then

Equivalents of H2O2 = Equivalents of KMnO4

moles of H202 X V.F of H202 = moles of KMnO4 X V.F of KMnO4

          ''''                                       = Molarity x volume x V.f of KMnO4

          ''''                                       = Normality x V.F of KMnO4   [N =M . V.f]

  thus,

 

(x/34) x 2 = 1 x 20/1000

x/17 = 0.02

x = 0.02*17

x = 0.34.

Thus Pure H202 in 0.2 gm sample is =

0.34/0.2 x 100

= 170 %

I hope this correct!

Whenever titration prob. comes try to use equivalents of each ractants and products if it is!

Thanks.

Sorry baby 'wink'