Question

0.2molar 300 ml H2SO4 soln mixed with 0.3 molar 200ml H2SO4 soln then what will be the 1) Final molarity
2) What volume of water is required to decrease the molarity of soln to 0.05 mole.

Answer 1

Answer:

hy mate your answer is below ..hope it helps u..

H2SO4 = 2MH+

H+ in 200 ml of one M h2so4

2× 0.2L× ONE MOL /L =0.4

0.3L × 3 mol /L = 0.9

1.5 ×2mol/L = 《0.9

2mol /L is equal to 0.2 = 1.5

total volume is 1 L

so (h+) is equal to 1.5 mol per l

hope it helps.

mark brainliest plz

Answer 2

Answer:

holla dude refer pic above please