0.2x +0.3y = 1.3
0.4 x + 0.5 y = 2.3 please solve substitution method
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0.2x+0.3y=1.3. .... (1)
0.4x+0.5y=2.3. .....(2)
multiply by 10 in equation (1) and (2) we get
2x+3y=13 ..... (3)
4x+5y=23 .....(4)
by (3) we get x=13-3y/2. .... (5)
substitute the value of x in (4) we get
4×(13-3y/2)+5y=23
26-6y+5y=23
26-y=23
y=3
substitute y=3 in (5)
x=(13-3×3)/2
13-9/2
4/2=2
by using substitution method we get
x=2 and y=3
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