0.2x+0.3y=1.3
0.4x+0.5y=2.3
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Step-by-step explanation:
Multiple 2 to eq 1
=>0.4x+0.6y=2.6
Subtracting eq 2 from eq 1
=>(0.4x+0.6y)-(0.4x+0.5y)=2.6-2.3
=>0.1y=0.3
=>y=3
substituting y
x=2
Therefore,x=2,y=3
Hope this helps
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