0.2x+0.3y=1.3 0.4x+0.5y=2.3 by substitution mehod please
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Answer:
0.2x+0.3y=1.3
2x+3y=13
0.4x+0.5y=2.3
4x+5y=23
equ1 2x=(13-3y)
x=(13-3y)/2
substitute this value in
4(13-3y)/2+5y=23
(52-12y)/2+5y=23
52-12y+10y=46
52-2y=46
52-46=2y
2y=6
y=3
therefore x=(13-3(3))/2
x=(13-9)/2
x=4/2
x=2
therefore x=2 and y=3
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