Question

0.2x+0.3y=1.3
0.4x+0.5y=2.3
Slove this by substitution method. ​

Answer 1

Multiplying both the equations by 10

So now it becomes ☺

2X + 3Y = 13 ( equ.1 )

4X + 5Y = 23 ( equ.2 )

Now in equ.1 ,

X = ( 13 - 3Y ) / 2

Substituting in Equ.2

4 x ( 13 - 3Y ) / 2 + 5Y = 23

26 - 6Y + 5Y = 23

Y = 26 - 23

Y = 3

Substituting in Equ.1

X = ( 13 - 3 x 3 ) / 2

X = ( 13 - 9 ) / 2

X = 4/2

X = 2

The value of X = 2 & Y = 3

Hope it helps ✌

Shreya ❤

Answer 2

Answer:

=> The value of x is 2 and y is 3.

Step-by-step explanation:

The given equations are

$0.2x+0.3y=1.3$

$0.4x+0.5y=2.3$

Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign.

$=> 0.2x+0.3y=1.3$

Subtract $\frac{3y}{10}$ from both sides of the equation.

$=> 0.2x=-0.3y+1.3$

Multiply both sides by $5$,

$=> x=5(-0.3y+1.3)$

Now, further calculating it we get:

$=> x=-1.5y+6.5$

Substitute $\frac{-3 y+13}{2}$for x in the other equation, $0.4 x+0.5 y=2.3$

$=> 0.4(-1.5y+6.5)+0.5y=2.3$

Multiply $0.4$ times$\frac{-3 y+13}{2}$

$=> -0.6 y+2.6+0.5 y=2.3$

Add $-\frac{3 y}{5}$ to $\frac{y}{2}$

$=> -0.1 y+2.6=2.3$

Subtract $2.6$ from both sides of the equation.

$=> -0.1 y=-0.3$

Multiply $-10$ on both sides,

$=> y = 3$

So, the value of y is 3.

Substitute $3$ for $y$ in $x=-1.5 y+6.5$

$=> x=-1.5 \times 3+6.5$

$=> x=\frac{-9+13}{2}$

$=> x =2$

So, the value of x is 2.