Math, asked by krishi70296, 5 hours ago

0.2x+0.3y=1.3 and 0.4x+0.5y=2.30.Solve the pair of linear equation by substitutionak method?​

Answers

Answered by sushil19gupta
1

Answer:

= 2 and y = 3

Step-by-step explanation:

Given :0.2x+0.3y=1.30.2x+0.3y=1.3

0.4x+ 0.5y=2.30.4x+0.5y=2.3

To Find : solve using substitution method

Solution :

0.2x+0.3y=1.30.2x+0.3y=1.3 -----1

0.4x+ 0.5y=2.30.4x+0.5y=2.3 ------2

Substitute the value of x from 1 in 2

0.4(\frac{1.3 - 0.3 y}{0.2})+ 0.5y=2.30.4(

0.2

1.3−0.3y

)+0.5y=2.3

y=3y=3

0.2x+0.3(3)=1.30.2x+0.3(3)=1.3

0.2x=1.3-0.90.2x=1.3−0.9

x=\frac{1.3-0.9}{0.2}x=

0.2

1.3−0.9

x=2x=2

So, x = 2 and y = 3

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